﻿// JavaScript Document
function show(object) {
	if (document.layers && document.layers[object] != null)
	    document.layers[object].visibility = 'visible';
	else if (document.all)
	    document.all[object].style.visibility = 'visible';
}

function hide(object) {
	if (document.layers && document.layers[object] != null)
	    document.layers[object].visibility = 'hidden';
	else if (document.all)
	    document.all[object].style.visibility = 'hidden';
}
function submitEmailid()
{
    if ((Trim(document.EmailOffer.Emailid.value)=="") || (document.EmailOffer.Emailid.value.indexOf("'", 0) == 1) || (document.EmailOffer.Emailid.value.indexOf("-", 0) == 1))
	{
		alert("Please enter Valid Email id");
		document.EmailOffer.Emailid.value=Trim(document.EmailOffer.Emailid.value);
		document.EmailOffer.Emailid.focus();
		return false;
	}
	if (CheckEMail()==false)
	{
		return false;
	}
	return true;
}

function CheckEMail()
{

	if (document.EmailOffer.Emailid.value!="")
		return fnCheckEMail();
}
function fnCheckEMail(){

	var emailStr;
	emailStr=document.EmailOffer.Emailid.value;
	//document.newmember.Email.value;
	//alert(emailStr);
	/* The following pattern is used to check if the entered e-mail address fits the user@domain format.  It also is used to
		separate the username  from the domain. */
	var emailPat=/^(.+)@(.+)$/;
	/* The following string represents the pattern for matching all special characters.  We don't want to allow special
	characters in the address.    These characters include ( ) < > @ , ; : \ " . [ ]   */
	var specialChars="\\(\\)<>@,;:\\\\\\\"\\.\\[\\]";
	/* The following string represents the range of characters allowed in a username or domainname.  It really states which
		chars aren't allowed. */
	var validChars="\[^\\s" + specialChars + "\]";
	/* The following pattern applies if the "user" is a quoted string (in which case, there are no rules about which
		characters are allowed and which aren't; anything goes).  E.g. "jiminy cricket"@disney.com
		is a legal e-mail address. */
	var quotedUser="(\"[^\"]*\")";
	/* The following pattern applies for domains that are IP addresses,rather than symbolic names.  E.g.joe@[123.124.233.4] is a legal
		e-mail address. NOTE: The square brackets are required. */
	var ipDomainPat=/^\[(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})\]$/;
	/* The following string represents an atom (basically a series of non-special characters.) */
	var atom=validChars + '+';
	/* The following string represents one word in the typical username.For example, in john.doe@somewhere.com, john and
		doe are words. Basically, a word is either an atom or quoted string. */
	var word="(" + atom + "|" + quotedUser + ")";
	// The following pattern describes the structure of the user
	var userPat=new RegExp("^" + word + "(\\." + word +")*$");
	/* The following pattern describes the structure of a normal symbolic domain, as opposed to ipDomainPat, shown above. */
	var domainPat=new RegExp("^" + atom + "(\\." + atom+")*$");
	/* Finally, let's start trying to figure out if the supplied address is  valid. */
	/* Begin with the coarse pattern to simply break up user@domain into different pieces that are easy to analyze. */
	var matchArray=emailStr.match(emailPat);
	
	if (matchArray==null) {
	  /* Too many/few @'s or something; basically, this address doesn't even fit the general mould of a valid e-mail
		 address. */
		alert("Email address seems incorrect (check @ and .'s)");
		document.EmailOffer.Emailid.focus();		 
		return false;
	}	
	var user=matchArray[1];
	var domain=matchArray[2];
	// See if "user" is valid 
	if (user.match(userPat)==null) {
		// user is not valid
	    alert("The username doesn't seem to be valid.")
	    document.EmailOffer.Emailid.focus();
	    return false;
	}
	/* if the e-mail address is at an IP address (as opposed to a symbolic host name) make sure the IP address is valid. */
	var IPArray=domain.match(ipDomainPat);
	if (IPArray!=null) {

		  for (var i=1;i<=4;i++) {
		    if (IPArray[i]>255) {
				alert("Destination IP address is invalid!");
		        document.EmailOffer.Emailid.focus();
			return false;
		    }
	    }
	    return true;
	}

	// Domain is symbolic name
	var domainArray=domain.match(domainPat);
	if (domainArray==null) {
		alert("The domain name doesn't seem to be valid.");
		document.EmailOffer.Emailid.focus();
	    return false;
	}
	/* domain name seems valid, but now make sure that it ends in a three-letter word (like com, edu, gov) or a two-letter word,
		representing country (uk, nl), and that there's a hostname preceding the domain or country. */
	/* Now we need to break up the domain to get a count of how many atoms it consists of. */
	var atomPat=new RegExp(atom,"g");
	var domArr=domain.match(atomPat);
	var len=domArr.length;
	if (domArr[domArr.length-1].length<2 || domArr[domArr.length-1].length>3) {
	      // the address must end in a two letter or three letter word.
		  alert("The address must end in a three-letter domain, or two letter country.");
		  document.EmailOffer.Emailid.focus();
	   return false;
	}
	// Make sure there's a host name preceding the domain.
	if (len<2) {
	   var errStr="This address is missing a hostname!";
	   alert(errStr);
	   document.EmailOffer.Emailid.focus();
	   return false;
	}
	return true;
}


function RTrim(String)
{
	var i = 0;
	var j = String.length - 1;

	if (String == null)
		return (false);

	for(j = String.length - 1; j >= 0; j--)
	{
		if (String.substr(j, 1) != ' ' &&
			String.substr(j, 1) != '\t')
		break;
	}

	if (i <= j)
		return (String.substr(i, (j+1)-i));
	else
		return ('');
}

function Trim(String)
{
	if (String == null)
	{
	  
		return (false);
	}
    
	return RTrim(LTrim(String));
}
function LTrim(String)
{
	var i = 0;
	var j = String.length - 1;

	if (String == null)
		return (false);

	for (i = 0; i < String.length; i++)
	{
		if (String.substr(i, 1) != ' ' &&
		    String.substr(i, 1) != '\t')
			break;
	}

	if (i <= j)
		return (String.substr(i, (j+1)-i));
	else
		return ('');
}
